What is the limit as x approaches infinity of log_{2}(((x+2))/((2*x+1))) ?

The limit as x approaches infinity of log_{2}(((x+2))/((2*x+1))) is -1

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limit as x approaches infinity of log_{2}(((x+2))/((2*x+1)))

x \to \infty lim (lo g_{2} (\frac{( x + 2 )}{( 2 \cdot x + 1 )}))

- 1

Solution steps

x \to \infty lim (lo g_{2} (\frac{x + 2}{2 x + 1}))

Apply the Limit Chain Rule:

- 1

= - 1

\int_{1}^{8} x - 1 d x

x^{2} x^{3} + 1

\int \frac{sec ^{2} ( θ )}{tan ( θ )} d θ

x^{^{''}} - 2 x^{^{'}} - 3 x = 0

\frac{d}{d x} (2 x y)

What is the limit as x approaches infinity of log_{2}(((x+2))/((2*x+1))) ?
The limit as x approaches infinity of log_{2}(((x+2))/((2*x+1))) is -1