What is the tangent of f(x)=x^2+5x-3,\at x=-3 ?

The tangent of f(x)=x^2+5x-3,\at x=-3 is y=-x-12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=x^2+5x-3,\at x=-3

tangent of

f (x) = x^{2} + 5 x - 3, at x = - 3

y = - x - 12

Solution steps

Find the tangent point:

(- 3, - 9)

Find the slope of

f (x) = x^{2} + 5 x - 3 : \frac{df ( x )}{d x} = 2 x + 5

Compute the slope of

f (x) = x^{2} + 5 x - 3

x = - 3 : m = - 1

Find the line with slope m=

- 1

and passing through

(- 3, - 9) : y = - x - 12

y = - x - 12

\frac{\partial}{\partial y} (e^{1 + x^{2} - y^{2}})

\frac{d}{d x} (\frac{3}{x ^{4} + 2})

\int_{0}^{2} 6 x^{2} - 18 x + 12 d x

f (x) = x^{2} - \frac{1}{x}, (2, 3.5)

n = 1 \sum \infty \frac{( ( - 7 ) ^{n - 1} )}{8 ^{n}}

What is the tangent of f(x)=x^2+5x-3,\at x=-3 ?
The tangent of f(x)=x^2+5x-3,\at x=-3 is y=-x-12