What is the derivative of 12sqrt(x)+16x^{3/4} ?

The derivative of 12sqrt(x)+16x^{3/4} is 6/(x^{1/2)}+(12)/(x^{1/4)}

What is the first derivative of 12sqrt(x)+16x^{3/4} ?

The first derivative of 12sqrt(x)+16x^{3/4} is 6/(x^{1/2)}+(12)/(x^{1/4)}

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derivative of

12 x + 16 x^{\frac{3}{4}}

\frac{6}{x ^{\frac{1}{2}}} + \frac{12}{x ^{\frac{1}{4}}}

Solution steps

\frac{d}{d x} (12 x + 16 x^{\frac{3}{4}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (12 x) + \frac{d}{d x} (16 x^{\frac{3}{4}})

\frac{d}{d x} (12 x) = \frac{6}{x ^{\frac{1}{2}}}

\frac{d}{d x} (16 x^{\frac{3}{4}}) = \frac{12}{x ^{\frac{1}{4}}}

= \frac{6}{x ^{\frac{1}{2}}} + \frac{12}{x ^{\frac{1}{4}}}

f (x) = x^{2} - 4, (- 2, 3)

x \to 1 lim (x (x - 1)^{- 1})

\frac{d}{d x} (in)

y^{^{''}} + a y^{^{'}} = 0

\int 12 cos (3 x) d x

What is the derivative of 12sqrt(x)+16x^{3/4} ?
The derivative of 12sqrt(x)+16x^{3/4} is 6/(x^{1/2)}+(12)/(x^{1/4)}
What is the first derivative of 12sqrt(x)+16x^{3/4} ?
The first derivative of 12sqrt(x)+16x^{3/4} is 6/(x^{1/2)}+(12)/(x^{1/4)}