What is area 6-y=x^2,y+8=x^2,x-y+4=0,x-y-6=0 ?

The answer to area 6-y=x^2,y+8=x^2,x-y+4=0,x-y-6=0 is No Solution

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area 6-y=x^2,y+8=x^2,x-y+4=0,x-y-6=0

area

6 - y = x^{2}, y + 8 = x^{2}, x - y + 4 = 0, x - y - 6 = 0

No Solution

Solution steps

Isolate

y

for

6 - y = x^{2} : y = - x^{2} + 6

Isolate

y

for

y + 8 = x^{2} : y = x^{2} - 8

Isolate

y

for

x - y + 4 = 0 : y = x + 4

Isolate

y

for

x - y - 6 = 0 : y = x - 6

f_{1} (x) = - x^{2} + 6

f_{2} (x) = x^{2} - 8

To find the intersection points solve

f_{i} (x) = f_{j} (x)

- x^{2} + 6 = x^{2} - 8 : x = 7, x = - 7

- x^{2} + 6 = x + 4 : x = - 2, x = 1

- x^{2} + 6 = x - 6 : x = - 4, x = 3

x^{2} - 8 = x + 4 : x = 4, x = - 3

x^{2} - 8 = x - 6 : x = 2, x = - 1

x + 4 = x - 6 :

No Solution

Curves not bounded

= No Solution

y^{^{''}} - 7 y^{^{'}} + 12 y = 0, y (0) = - 2, y^{^{'}} (0) = 4

\frac{d}{d x} (\frac{1}{x + sin ( x )})

\frac{d y}{d x} = \frac{4 e ^{4 x}}{e ^{y}}

\int 2 e^{- s t} d t

\frac{( s - 1 )}{s ^{2} + 2 s + 2}

What is area 6-y=x^2,y+8=x^2,x-y+4=0,x-y-6=0 ?
The answer to area 6-y=x^2,y+8=x^2,x-y+4=0,x-y-6=0 is No Solution