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Popular >

y^'+y/(x+1)=0

Solution

y^{^{'}} + \frac{y}{x + 1} = 0

Solution

y = \frac{c _{1}}{x + 1}

Solution steps

y^{'} (x) + \frac{y}{x + 1} = 0

Solve separable ODE:

y = \frac{c _{1}}{x + 1}

y = \frac{c _{1}}{x + 1}

Popular Examples

derivative of 1/9 (1-(3x+1e^{-3x}))

\frac{d}{d x} (\frac{1}{9} (1 - (3 x + 1) e^{- 3 x}))

derivative of y=(8x^2+2x+8)/(sqrt(x))derivative of

y = \frac{8 x ^{2} + 2 x + 8}{x}

derivative of x/(x^2+2)derivative of

\frac{x}{x ^{2} + 2}

derivative of (e^{2x}-e^x+e^{-3x}/(e^x))

\frac{d}{d x} (\frac{e ^{2 x} - e ^{x} + e ^{- 3 x}}{e ^{x}})

(\partial)/(\partial x)(2x)

\frac{\partial}{\partial x} (2 x)

Frequently Asked Questions (FAQ)

What is the solution for y^'+y/(x+1)=0 ?
The solution for y^'+y/(x+1)=0 is y=(c_{1})/(x+1)