What is area sin^2(x),sin^4(x),0,pi ?

The answer to area sin^2(x),sin^4(x),0,pi is pi/8

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area sin^2(x),sin^4(x),0,pi

area

sin^{2} (x), sin^{4} (x), 0, π

\frac{π}{8}

Decimal Notation

0.39269 \dots

Solution steps

Apply the area formula:

\int_{0}^{π} ∣ cos (x) ∣^{2} ∣ sin (x) ∣^{2} d x

Solve

\int_{0}^{π} ∣ cos (x) ∣^{2} ∣ sin (x) ∣^{2} d x : \frac{π}{8}

The area is:

= \frac{π}{8}

\frac{d}{d x} ((2)^{x})

4 x - x^{2}

\int cos (9 x) sin (5 x) d x

y^{3} - (18 x + 6) + 3 x y^{2} \frac{d y}{d x} = 0

\frac{d}{d x} ((\frac{1 + sin ( 3 x )}{3 - 2 x})^{- 1})

What is area sin^2(x),sin^4(x),0,pi ?
The answer to area sin^2(x),sin^4(x),0,pi is pi/8