What is the derivative of (sqrt(1+x))/2 ?

The derivative of (sqrt(1+x))/2 is 1/(4sqrt(1+x))

What is the first derivative of (sqrt(1+x))/2 ?

The first derivative of (sqrt(1+x))/2 is 1/(4sqrt(1+x))

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derivative of

\frac{1 + x}{2}

\frac{1}{4 1 + x}

Solution steps

\frac{d}{d x} (\frac{1 + x}{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (1 + x)

Apply the chain rule:

\frac{1}{2 1 + x} \frac{d}{d x} (1 + x)

= \frac{1}{2 1 + x} \frac{d}{d x} (1 + x)

\frac{d}{d x} (1 + x) = 1

= \frac{1}{2} \cdot \frac{1}{2 1 + x} \cdot 1

Simplify

\frac{1}{2} \cdot \frac{1}{2 1 + x} \cdot 1 : \frac{1}{4 1 + x}

= \frac{1}{4 1 + x}

- 2 x^{2}, at x = 0

\frac{d}{d x} (\frac{2}{e ^{x} + \frac{1}{e ^{x}}})

\int \frac{1 - t ^{2}}{t ^{4}} d t

\int 10 ln (x^{2} - 1) d x

\frac{2 x - 6}{x + 1}, at x = 0

What is the derivative of (sqrt(1+x))/2 ?
The derivative of (sqrt(1+x))/2 is 1/(4sqrt(1+x))
What is the first derivative of (sqrt(1+x))/2 ?
The first derivative of (sqrt(1+x))/2 is 1/(4sqrt(1+x))