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Popular >

derivative of (2x^3+8)/x

Solution

derivative of

\frac{2 x ^{3} + 8}{x}

Solution

\frac{4 x ^{3} - 8}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{2 x ^{3} + 8}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 x ^{3} + 8 ) x - \frac{d x}{d x} ( 2 x ^{3} + 8 )}{x ^{2}}

\frac{d}{d x} (2 x^{3} + 8) = 6 x^{2}

\frac{d x}{d x} = 1

= \frac{6 x ^{2} x - 1 \cdot ( 2 x ^{3} + 8 )}{x ^{2}}

Simplify

\frac{6 x ^{2} x - 1 \cdot ( 2 x ^{3} + 8 )}{x ^{2}} : \frac{4 x ^{3} - 8}{x ^{2}}

= \frac{4 x ^{3} - 8}{x ^{2}}

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(\partial)/(\partial x)(sqrt(90-4x^2-1y^2))

\frac{\partial}{\partial x} (90 - 4 x^{2} - 1 y^{2})

y^'=(t^2)/y (1+t^3)

y^{^{'}} = \frac{t ^{2}}{y} (1 + t^{3})

integral from 0 to 13 of 8x

\int_{0}^{13} 8 x d x

Frequently Asked Questions (FAQ)

What is the derivative of (2x^3+8)/x ?
The derivative of (2x^3+8)/x is (4x^3-8)/(x^2)
What is the first derivative of (2x^3+8)/x ?
The first derivative of (2x^3+8)/x is (4x^3-8)/(x^2)