What is the solution for -10x^2y+y^'=5x^2 ?

The solution for -10x^2y+y^'=5x^2 is y=(e^{(10x^3+c_{1})/3})/(2)-1/2

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-10x^2y+y^'=5x^2

- 10 x^{2} y + y^{^{'}} = 5 x^{2}

y = \frac{e ^{\frac{10 x ^{3} + c _{1}}{3}}}{2} - \frac{1}{2}

Solution steps

- 10 x^{2} y + y^{'} (x) = 5 x^{2}

Solve separable ODE:

y = \frac{e ^{\frac{10 x ^{3} + c _{1}}{3}}}{2} - \frac{1}{2}

y = \frac{e ^{\frac{10 x ^{3} + c _{1}}{3}}}{2} - \frac{1}{2}

x \to 5 + lim (lo g_{3} (x - 5))

x \to 0 lim (\frac{4}{e ^{x} + 1})

x \to 1 lim (\frac{( 1 + x ) ( 1 - x )}{x \cdot \frac{s i n ( π x )}{x}})

\int \frac{1}{x ^{2} + 6} d x

\frac{\partial}{\partial x} (\frac{2 x - 3 t}{3 x + 5 t})

What is the solution for -10x^2y+y^'=5x^2 ?
The solution for -10x^2y+y^'=5x^2 is y=(e^{(10x^3+c_{1})/3})/(2)-1/2