What is the integral of 2x^2-4x-6 ?

The integral of 2x^2-4x-6 is (2x^3)/3-2x^2-6x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 2x^2-4x-6

\int 2 x^{2} - 4 x - 6 d x

\frac{2 x ^{3}}{3} - 2 x^{2} - 6 x + C

Solution steps

\int 2 x^{2} - 4 x - 6 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x^{2} d x - \int 4 x d x - \int 6 d x

\int 2 x^{2} d x = \frac{2 x ^{3}}{3}

\int 4 x d x = 2 x^{2}

\int 6 d x = 6 x

= \frac{2 x ^{3}}{3} - 2 x^{2} - 6 x

Add a constant to the solution

= \frac{2 x ^{3}}{3} - 2 x^{2} - 6 x + C

\frac{d}{d x} (x^{\frac{9}{x}})

\frac{d y}{d t} = 2100 - 300 (\frac{y}{17000})

\int \frac{5}{x ^{6}} d x

\frac{d}{d x} (ln ((x + 3)^{- 1}))

x \to 0 lim (\frac{x ^{2} + 2 x - 1}{x})

What is the integral of 2x^2-4x-6 ?
The integral of 2x^2-4x-6 is (2x^3)/3-2x^2-6x+C