What is the integral from 0 to 1 of t^2 ?

The integral from 0 to 1 of t^2 is 1/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of t^2

\int_{0}^{1} t^{2} d t

\frac{1}{3}

Decimal Notation

0.33333 \dots

Solution steps

\int_{0}^{1} t^{2} d t

Apply the Power Rule

: [\frac{t ^{3}}{3}]_{0}^{1}

= [\frac{t ^{3}}{3}]_{0}^{1}

Compute the boundaries:

\frac{1}{3}

= \frac{1}{3}

x^{2} e^{x} - 2 x e^{x} + 4 e^{x}

8 ln (x)

\frac{d}{d x} (e^{x^{2} + 1})

y^{^{'}} = 20 - 5 y

\int sin^{2} (x) x d x

What is the integral from 0 to 1 of t^2 ?
The integral from 0 to 1 of t^2 is 1/3