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Popular >

y^{''}-y^'=x

Solution

y^{^{''}} - y^{^{'}} = x

Solution

y = c_{1} e^{x} + c_{2} - \frac{x ^{2}}{2} - x

Solution steps

y^{''} (x) - y^{'} (x) = x

Solve linear ODE:

y = c_{1} e^{x} + c_{2} - \frac{x ^{2}}{2} - x

y = c_{1} e^{x} + c_{2} - \frac{x ^{2}}{2} - x

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Frequently Asked Questions (FAQ)

What is the solution for y^{''}-y^'=x ?
The solution for y^{''}-y^'=x is y=c_{1}e^x+c_{2}-(x^2)/2-x