What is the integral of (15\sqrt[4]{x})/4 ?

The integral of (15\sqrt[4]{x})/4 is 3x^{5/4}+C

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integral of (15\sqrt[4]{x})/4

3 x^{\frac{5}{4}} + C

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply the Power Rule

: \frac{4}{5} x^{\frac{5}{4}}

= \frac{15}{4} \cdot \frac{4}{5} x^{\frac{5}{4}}

Simplify

\frac{15}{4} \cdot \frac{4}{5} x^{\frac{5}{4}} : 3 x^{\frac{5}{4}}

= 3 x^{\frac{5}{4}}

Add a constant to the solution

= 3 x^{\frac{5}{4}} + C

x \to - 1 lim (x + 2)

\frac{\partial}{\partial x} (18 x y)

x + y - 1 + (x - y + 3) y^{^{'}} = 0

5 x^{2} e^{x}

\int_{0}^{1} (2 x + 3) e^{- 5 x} d x

What is the integral of (15\sqrt[4]{x})/4 ?
The integral of (15\sqrt[4]{x})/4 is 3x^{5/4}+C