What is the derivative of 3e^x+2/(\sqrt[3]{x}) ?

The derivative of 3e^x+2/(\sqrt[3]{x}) is 3e^x-2/(3x^{4/3)}

What is the first derivative of 3e^x+2/(\sqrt[3]{x}) ?

The first derivative of 3e^x+2/(\sqrt[3]{x}) is 3e^x-2/(3x^{4/3)}

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3 e^{x} - \frac{2}{3 x ^{\frac{4}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (3 e^{x}) = 3 e^{x}

= 3 e^{x} - \frac{2}{3 x ^{\frac{4}{3}}}

\int x^{2} 2 x^{3} + 1 d x

2 y^{^{'}} + 4 y = - 8 y^{3}

y = f (y, x) (g (x))

\frac{d}{d x} (x y z)

x \to - 0.999 lim (\frac{1}{x ^{2}})

What is the derivative of 3e^x+2/(\sqrt[3]{x}) ?
The derivative of 3e^x+2/(\sqrt[3]{x}) is 3e^x-2/(3x^{4/3)}
What is the first derivative of 3e^x+2/(\sqrt[3]{x}) ?
The first derivative of 3e^x+2/(\sqrt[3]{x}) is 3e^x-2/(3x^{4/3)}