What is the limit as h approaches 0 of ((2+h)^3-8)/h ?

The limit as h approaches 0 of ((2+h)^3-8)/h is 12

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limit as h approaches 0 of ((2+h)^3-8)/h

h \to 0 lim (\frac{( 2 + h ) ^{3} - 8}{h})

12

Solution steps

h \to 0 lim (\frac{( 2 + h ) ^{3} - 8}{h})

Simplify

\frac{( 2 + h ) ^{3} - 8}{h} : h^{2} + 6 h + 12

= h \to 0 lim (h^{2} + 6 h + 12)

Plug in the value

h = 0

= 0^{2} + 6 \cdot 0 + 12

Simplify

= 12

x \to \infty lim (x)

f (x) =, 4 x^{3} + 2 t + 9

f (x) = (2 x + 3)^{1.4}

\int \frac{( x ^{2} + 1 ) ( x ^{2} - 2 )}{x ^{\frac{2}{3}}} d x

What is the limit as h approaches 0 of ((2+h)^3-8)/h ?
The limit as h approaches 0 of ((2+h)^3-8)/h is 12