What is the tangent of f(x)=11x^2+6x,\at x=2 ?

The tangent of f(x)=11x^2+6x,\at x=2 is y=50x-44

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tangent of f(x)=11x^2+6x,\at x=2

tangent of

f (x) = 11 x^{2} + 6 x, at x = 2

y = 50 x - 44

Solution steps

Find the tangent point:

(2, 56)

Find the slope of

f (x) = 11 x^{2} + 6 x : \frac{df ( x )}{d x} = 22 x + 6

Compute the slope of

f (x) = 11 x^{2} + 6 x

x = 2 : m = 50

Find the line with slope m=

50

and passing through

(2, 56) : y = 50 x - 44

y = 50 x - 44

x \to - 5 - lim (4 x + 25)

\int \frac{r}{1 + r ^{2}} d r

f (x) = sec (x), at x = \frac{π}{6}

\int \frac{1}{y ^{2} + 2} d y

\frac{\partial}{\partial x} (12 - x^{2} - y^{2})

What is the tangent of f(x)=11x^2+6x,\at x=2 ?
The tangent of f(x)=11x^2+6x,\at x=2 is y=50x-44