What is the solution for (dy}{dx}=\frac{-2x)/y ,y(0)=1 ?

The solution for (dy}{dx}=\frac{-2x)/y ,y(0)=1 is y=sqrt(-2x^2+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy}{dx}=\frac{-2x)/y ,y(0)=1

\frac{d y}{d x} = \frac{- 2 x}{y}, y (0) = 1

y = - 2 x^{2} + 1

Solution steps

\frac{d y}{d x} = \frac{- 2 x}{y}

Solve separable ODE:

y = - 2 x^{2} + 1

y = - 2 x^{2} + 1

\frac{d}{d x} (6 x + e^{- x})

(x^{2} y - x) d y + y d x = 0

\frac{d}{d x} (\frac{10}{x ^{7}})

y = 9 x, y = \frac{1}{3} x, y = 10 - x^{2}

tan (x y)

What is the solution for (dy}{dx}=\frac{-2x)/y ,y(0)=1 ?
The solution for (dy}{dx}=\frac{-2x)/y ,y(0)=1 is y=sqrt(-2x^2+1)