What is the derivative of 1-8u^2 ?

The derivative of 1-8u^2 is -16u

What is the first derivative of 1-8u^2 ?

The first derivative of 1-8u^2 is -16u

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derivative of

1 - 8 u^{2}

- 16 u

Solution steps

\frac{d}{d u} (1 - 8 u^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d u} (1) - \frac{d}{d u} (8 u^{2})

\frac{d}{d u} (1) = 0

\frac{d}{d u} (8 u^{2}) = 16 u

= 0 - 16 u

Simplify

= - 16 u

\int_{0}^{1} 2 π x (e^{- x^{2}}) d x

\frac{\partial}{\partial x} (- x e^{- 2 x y})

\frac{d ^{2}}{d x ^{2}} (θ cos (θ))

x \to 0 lim (1 - \frac{x ^{2}}{4})

x \to 4 lim (16 - x^{2})