What is the derivative of y=x^{2/3} ?

The derivative of y=x^{2/3} is 2/(3x^{1/3)}

What is the first derivative of y=x^{2/3} ?

The first derivative of y=x^{2/3} is 2/(3x^{1/3)}

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derivative of

y = x^{\frac{2}{3}}

\frac{2}{3 x ^{\frac{1}{3}}}

Solution steps

\frac{d}{d x} (x^{\frac{2}{3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{2}{3} x^{\frac{2}{3} - 1}

Simplify

\frac{2}{3} x^{\frac{2}{3} - 1} : \frac{2}{3 x ^{\frac{1}{3}}}

= \frac{2}{3 x ^{\frac{1}{3}}}

\frac{d}{d x} ((x^{3} - 5 x) (x + 2))

\int \frac{x ^{\frac{1}{3}}}{x ^{\frac{4}{3}} + 4} d x

\frac{d y}{d x} + 4 y = \frac{4}{3}

\frac{\partial}{\partial x} (2 x e^{y} - x cos (x y) + 2 y)

y^{^{''}} + 45 y^{^{'}} + 20 y = 0

What is the derivative of y=x^{2/3} ?
The derivative of y=x^{2/3} is 2/(3x^{1/3)}
What is the first derivative of y=x^{2/3} ?
The first derivative of y=x^{2/3} is 2/(3x^{1/3)}