What is the tangent of y^4-4y^2=x^4-9x^2,(-3,2) ?

The tangent of y^4-4y^2=x^4-9x^2,(-3,2) is y=-27/8 x-65/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y^4-4y^2=x^4-9x^2,(-3,2)

tangent of

y^{4} - 4 y^{2} = x^{4} - 9 x^{2}, (- 3, 2)

y = - \frac{27}{8} x - \frac{65}{8}

Solution steps

Find the slope of

y^{4} - 4 y^{2} = x^{4} - 9 x^{2} : \frac{d y}{d x} = \frac{x ( 2 x ^{2} - 9 )}{2 y ( y ^{2} - 2 )}

Compute the slope of

y^{4} - 4 y^{2} = x^{4} - 9 x^{2}

(- 3, 2) : m = - \frac{27}{8}

Find the line with slope m=

- \frac{27}{8}

and passing through

(- 3, 2) : y = - \frac{27}{8} x - \frac{65}{8}

y = - \frac{27}{8} x - \frac{65}{8}

y = e^{4 x} cos (7 x)

4 x ln (x)

\frac{\partial}{\partial y} (5 x^{2} - 3 x y^{2} + x yz)

n \to \infty lim (2 n)

x \to \infty lim (\frac{2 x ^{2}}{- x + 2})

What is the tangent of y^4-4y^2=x^4-9x^2,(-3,2) ?
The tangent of y^4-4y^2=x^4-9x^2,(-3,2) is y=-27/8 x-65/8