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Popular >

y^'=4y+a

Solution

y^{^{'}} = 4 y + a

Solution

y = \frac{e ^{4 t + c_{1}}}{4} - \frac{a}{4}

Solution steps

y^{'} (t) = 4 y + a

Solve separable ODE:

y = \frac{e ^{4 t + c_{1}}}{4} - \frac{a}{4}

y = \frac{e ^{4 t + c_{1}}}{4} - \frac{a}{4}

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Frequently Asked Questions (FAQ)

What is the solution for y^'=4y+a ?
The solution for y^'=4y+a is y=(e^{4t+c_{1}})/4-a/4