What is the solution for (dy)/(dx)=sin^2(y) ?

The solution for (dy)/(dx)=sin^2(y) is y=arccot(-x-c_{1})+pin

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(dy)/(dx)=sin^2(y)

\frac{d y}{d x} = sin^{2} (y)

y = arccot (- x - c_{1}) + πn

Solution steps

\frac{d y}{d x} = sin^{2} (y)

Solve separable ODE:

y = arccot (- x - c_{1}) + πn

y = arccot (- x - c_{1}) + πn

\frac{d}{d x} (arcsec (\frac{1}{2 x ^{2} - 1}))

\int \frac{x ^{2} + 1}{x ^{3} - 6 x ^{2} + 12 x - 8} d x

\int \frac{u ^{3}}{u + 1} d u

y^{^{'}} + 3 y = 2 sin (3 t)

\frac{x ^{2} - 35}{x - 6}

What is the solution for (dy)/(dx)=sin^2(y) ?
The solution for (dy)/(dx)=sin^2(y) is y=arccot(-x-c_{1})+pin