What is the derivative of y=x^3-3x+2 ?

The derivative of y=x^3-3x+2 is 3x^2-3

What is the first derivative of y=x^3-3x+2 ?

The first derivative of y=x^3-3x+2 is 3x^2-3

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derivative of

y = x^{3} - 3 x + 2

3 x^{2} - 3

Solution steps

\frac{d}{d x} (x^{3} - 3 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (2)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2) = 0

= 3 x^{2} - 3 + 0

Simplify

= 3 x^{2} - 3

x^{3} - 3 x + 2

y = 3 x - 2, x = 2, x = 4, y = 0

2 t (3 t^{2} - 7)^{5}

\int 225 - x^{2} d x

x \to 4 lim (5 x - 4)

What is the derivative of y=x^3-3x+2 ?
The derivative of y=x^3-3x+2 is 3x^2-3
What is the first derivative of y=x^3-3x+2 ?
The first derivative of y=x^3-3x+2 is 3x^2-3