What is the solution for x^2y^{''}-6xy^'+10y=-8x^3 ?

The solution for x^2y^{''}-6xy^'+10y=-8x^3 is y=c_{1}x^5+c_{2}x^2+4x^3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2y^{''}-6xy^'+10y=-8x^3

x^{2} y^{^{''}} - 6 x y^{^{'}} + 10 y = - 8 x^{3}

y = c_{1} x^{5} + c_{2} x^{2} + 4 x^{3}

Solution steps

x^{2} y^{''} (x) - 6 x y^{'} (x) + 10 y = - 8 x^{3}

Solve linear ODE:

y = c_{1} x^{5} + c_{2} x^{2} + 4 x^{3}

y = c_{1} x^{5} + c_{2} x^{2} + 4 x^{3}

\int_{- 4}^{4} \frac{1}{2} (1 6^{2} - x^{4}) d x

\int cos (3 x + 1) d x

x \to 0 lim (4 sin (x) - 1)

\int_{0}^{4} x d x

x \to 0 - lim (x - 2)

What is the solution for x^2y^{''}-6xy^'+10y=-8x^3 ?
The solution for x^2y^{''}-6xy^'+10y=-8x^3 is y=c_{1}x^5+c_{2}x^2+4x^3