What is the derivative of 3x^2+4x-5 ?

The derivative of 3x^2+4x-5 is 6x+4

What is the first derivative of 3x^2+4x-5 ?

The first derivative of 3x^2+4x-5 is 6x+4

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\frac{d}{d x} (3 x^{2} + 4 x - 5)

6 x + 4

Solution steps

\frac{d}{d x} (3 x^{2} + 4 x - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (4 x) - \frac{d}{d x} (5)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (5) = 0

= 6 x + 4 - 0

Simplify

= 6 x + 4

\int \frac{1}{x ^{\frac{2}{3}} ( 1 + x ^{\frac{1}{3}} )} d x

e^{x} - 1

x \to 1 lim ((x - 1)^{2})

\frac{\partial}{\partial x} (x^{3} + 2 x y - y^{2})

y = \frac{3}{4 x ^{5}}

What is the derivative of 3x^2+4x-5 ?
The derivative of 3x^2+4x-5 is 6x+4
What is the first derivative of 3x^2+4x-5 ?
The first derivative of 3x^2+4x-5 is 6x+4