What is the solution for x^{''}+ax=0 ?

The solution for x^{''}+ax=0 is x=c_{1}cos(sqrt(a)t)+c_{2}sin(sqrt(a)t)

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x^{''}+ax=0

x^{^{''}} + a x = 0

x = c_{1} cos (a t) + c_{2} sin (a t)

Solution steps

x^{''} (t) + a x (t) = 0

Solve linear ODE:

x = c_{1} cos (a t) + c_{2} sin (a t)

x = c_{1} cos (a t) + c_{2} sin (a t)

16 y^{^{''}} + 24 y^{^{'}} + 9 y = 0

\int 6 r 4 - r^{2} d r

\frac{d y}{d x} = e^{x + 2 y}

\frac{d y}{d x} = y (y + 2)

x \to 11 lim (\frac{2 x ^{2} - 12 x - 110}{x ^{2} - 121})

What is the solution for x^{''}+ax=0 ?
The solution for x^{''}+ax=0 is x=c_{1}cos(sqrt(a)t)+c_{2}sin(sqrt(a)t)