What is the solution for (dy)/(dx)=((x-1))/(y+2) ?

The solution for (dy)/(dx)=((x-1))/(y+2) is y=-2+sqrt(x^2-2x+c_{1)+4},y=-sqrt(x^2-2x+c_{1)+4}-2

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(dy)/(dx)=((x-1))/(y+2)

\frac{d y}{d x} = \frac{( x - 1 )}{y + 2}

y = - 2 + x^{2} - 2 x + c_{1} + 4, y = - x^{2} - 2 x + c_{1} + 4 - 2

Solution steps

\frac{d y}{d x} = \frac{( x - 1 )}{y + 2}

Solve separable ODE:

y = - 2 + x^{2} - 2 x + c_{1} + 4, y = - x^{2} - 2 x + c_{1} + 4 - 2

y = - 2 + x^{2} - 2 x + c_{1} + 4, y = - x^{2} - 2 x + c_{1} + 4 - 2

\int \frac{x + 2}{4 - 2 x - x ^{2}} d x

\int_{0}^{1} 13 \frac{1}{x ^{p}} d x

\frac{\partial}{\partial x} (5 x y e^{- y^{2}})

\int (\frac{15}{x ^{4}} + \frac{8}{x ^{5}}) d x

\frac{d}{d x} (\frac{sin ( 3 x )}{x})

What is the solution for (dy)/(dx)=((x-1))/(y+2) ?
The solution for (dy)/(dx)=((x-1))/(y+2) is y=-2+sqrt(x^2-2x+c_{1)+4},y=-sqrt(x^2-2x+c_{1)+4}-2