What is the derivative of f(x)=3x^2+2x+1 ?

The derivative of f(x)=3x^2+2x+1 is 6x+2

What is the first derivative of f(x)=3x^2+2x+1 ?

The first derivative of f(x)=3x^2+2x+1 is 6x+2

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derivative of

f (x) = 3 x^{2} + 2 x + 1

6 x + 2

Solution steps

\frac{d}{d x} (3 x^{2} + 2 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (2 x) + \frac{d}{d x} (1)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 6 x + 2 + 0

Simplify

= 6 x + 2

x^{2} - 4 x + 7, 2 x^{2} - 3 x + 1

y = 4 x^{2} - 5 x

x sin (5 x)

- 2 sin (x), at x = - \frac{π}{3}

\int_{3}^{0} x^{2} d x

What is the derivative of f(x)=3x^2+2x+1 ?
The derivative of f(x)=3x^2+2x+1 is 6x+2
What is the first derivative of f(x)=3x^2+2x+1 ?
The first derivative of f(x)=3x^2+2x+1 is 6x+2