What is the limit as x approaches 0+of e^x-(1+x) ?

The limit as x approaches 0+of e^x-(1+x) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0+of e^x-(1+x)

x \to 0 + lim (e^{x} - (1 + x))

0

Solution steps

x \to 0 + lim (e^{x} - (1 + x))

Plug in the value

x = 0

= e^{0} - (1 + 0)

Simplify

= 0

\frac{\partial}{\partial x} (x \cdot arccsc (\frac{x}{2}))

\int 5 x^{2} + 1 d x

\int \frac{a e ^{x} + b}{a e ^{x} - b} d x

(9 x y^{2} - 4 y) + (9 x^{2} y - 4 x) y^{^{'}} = 0

\int (csc (3 x) - cot (3 x))^{2} d x

What is the limit as x approaches 0+of e^x-(1+x) ?
The limit as x approaches 0+of e^x-(1+x) is 0