What is derivative of f(x)=e^θsin(6θ) ?

The answer to derivative of f(x)=e^θsin(6θ) is derivative of θ=0

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derivative of f(x)=e^θsin(6θ)

derivative of

f (x) = e^{θ} sin (6 θ)

\frac{d}{d x} (θ) = 0

Solution steps

f (x) = e^{θ} sin (6 θ)

Treat

θ

θ (x)

Differentiate both sides:

0 = e^{θ} \frac{d}{d x} (θ) sin (6 θ) + cos (6 θ) \cdot 6 \frac{d}{d x} (θ) e^{θ}

Isolate

\frac{d}{d x} (θ) : \frac{d}{d x} (θ) = 0

\frac{d}{d x} (θ) = 0

x \to 2 lim (3 x^{2} - x + 5)

\frac{\partial}{\partial x} (- 5 x^{2} - 5 y^{2} + x y)

y y^{^{'}} = 3 (\frac{y ^{2} - 2}{x ^{3}}) x^{2}

\frac{d}{d x} ((\frac{x + 9}{x - 9})^{5})

x \to - 6 - lim (\frac{x + 2}{x + 6})

What is derivative of f(x)=e^θsin(6θ) ?
The answer to derivative of f(x)=e^θsin(6θ) is derivative of θ=0