What is the derivative of f(x)=x^2+3x^6 ?

The derivative of f(x)=x^2+3x^6 is 2x+18x^5

What is the first derivative of f(x)=x^2+3x^6 ?

The first derivative of f(x)=x^2+3x^6 is 2x+18x^5

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derivative of

f (x) = x^{2} + 3 x^{6}

2 x + 18 x^{5}

Solution steps

\frac{d}{d x} (x^{2} + 3 x^{6})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (3 x^{6})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x^{6}) = 18 x^{5}

= 2 x + 18 x^{5}

\frac{\partial}{\partial x} (e^{2 y})

\frac{\partial}{\partial y} (x^{2} y + x + y)

x \to 1 lim (- x^{2} + 5 x - 7)

\frac{\partial}{\partial y} (x + y cos (x))

f (x) = sin^{5} (x)

What is the derivative of f(x)=x^2+3x^6 ?
The derivative of f(x)=x^2+3x^6 is 2x+18x^5
What is the first derivative of f(x)=x^2+3x^6 ?
The first derivative of f(x)=x^2+3x^6 is 2x+18x^5