What is the derivative of y=(3x^2+2)(4x-1) ?

The derivative of y=(3x^2+2)(4x-1) is 36x^2-6x+8

What is the first derivative of y=(3x^2+2)(4x-1) ?

The first derivative of y=(3x^2+2)(4x-1) is 36x^2-6x+8

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derivative of

y = (3 x^{2} + 2) (4 x - 1)

36 x^{2} - 6 x + 8

Solution steps

\frac{d}{d x} ((3 x^{2} + 2) (4 x - 1))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 3 x^{2} + 2, g = 4 x - 1

= \frac{d}{d x} (3 x^{2} + 2) (4 x - 1) + \frac{d}{d x} (4 x - 1) (3 x^{2} + 2)

\frac{d}{d x} (3 x^{2} + 2) = 6 x

\frac{d}{d x} (4 x - 1) = 4

= 6 x (4 x - 1) + 4 (3 x^{2} + 2)

Simplify

6 x (4 x - 1) + 4 (3 x^{2} + 2) : 36 x^{2} - 6 x + 8

= 36 x^{2} - 6 x + 8

\frac{d}{d x} (\frac{e ^{x}}{x ^{2}})

\int \frac{2 x + 1}{x ^{2} - 3 x + 2} d x

y^{^{''}} + 4 y = e - t

y^{^{''}} - 2 y^{^{'}} = 6 e^{2 x}

What is the derivative of y=(3x^2+2)(4x-1) ?
The derivative of y=(3x^2+2)(4x-1) is 36x^2-6x+8
What is the first derivative of y=(3x^2+2)(4x-1) ?
The first derivative of y=(3x^2+2)(4x-1) is 36x^2-6x+8