What is (\partial)/(\partial x)((2+4y^2)x-3x^2) ?

The answer to (\partial)/(\partial x)((2+4y^2)x-3x^2) is 2+4y^2-6x

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(\partial)/(\partial x)((2+4y^2)x-3x^2)

\frac{\partial}{\partial x} ((2 + 4 y^{2}) x - 3 x^{2})

2 + 4 y^{2} - 6 x

Solution steps

\frac{\partial}{\partial x} ((2 + 4 y^{2}) x - 3 x^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} ((2 + 4 y^{2}) x) - \frac{\partial}{\partial x} (3 x^{2})

\frac{\partial}{\partial x} ((2 + 4 y^{2}) x) = 2 + 4 y^{2}

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

= 2 + 4 y^{2} - 6 x

\int \frac{x ^{2} + 5}{x} d x

\frac{x ^{2}}{5 + x}

y = \frac{14}{1 + e ^{- x}}, (0, 7)

\int 13 ln (x^{2} - x + 6) d x

What is (\partial)/(\partial x)((2+4y^2)x-3x^2) ?
The answer to (\partial)/(\partial x)((2+4y^2)x-3x^2) is 2+4y^2-6x