What is (\partial)/(\partial x)(x^2-y/4) ?

The answer to (\partial)/(\partial x)(x^2-y/4) is 2x

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(\partial)/(\partial x)(x^2-y/4)

\frac{\partial}{\partial x} (x^{2} - \frac{y}{4})

2 x

Solution steps

\frac{\partial}{\partial x} (x^{2} - \frac{y}{4})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (\frac{y}{4})

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (\frac{y}{4}) = 0

= 2 x - 0

Simplify

= 2 x

n = 2 \sum \infty \frac{1}{n ^{3} + n}

\frac{d}{d x} (ln (3 x^{2} - cos (x)))

y^{^{'}} - y tan (x) = sec (x)

(3 x - 3)^{2} (1 - 5 x)^{4}

3 t + 2

What is (\partial)/(\partial x)(x^2-y/4) ?
The answer to (\partial)/(\partial x)(x^2-y/4) is 2x