What is area x^2-4,y=0,x=-4,x=3 ?

The answer to area x^2-4,y=0,x=-4,x=3 is 71/3

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area x^2-4,y=0,x=-4,x=3

area

x^{2} - 4, y = 0, x = - 4, x = 3

\frac{71}{3}

Decimal Notation

23.66666 \dots

Solution steps

Apply the area formula:

\int_{- 4}^{3} x^{2} - 4 d x

Solve

\int_{- 4}^{3} x^{2} - 4 d x : \frac{71}{3}

The area is:

= \frac{71}{3}

\frac{d}{d x} (ln (\frac{a + b x}{a - b x}))

\frac{1}{s ^{2} + 4 s + 12}

\frac{d}{d x} ((7 x + 3)^{2})

\frac{d}{d x} ((3 x^{3} + 1) (- 4 x^{2} - 3)^{4})

x \to 4 lim (\frac{x ^{2} - 6}{x - 4})