What is the integral from 0 to 0.75 of 2x ?

The integral from 0 to 0.75 of 2x is 0.5625

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integral from 0 to 0.75 of 2x

\int_{0}^{0.75} 2 x d x

0.5625

Solution steps

\int_{0}^{0.75} 2 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{0.75} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{0.75}

= 2 [\frac{x ^{2}}{2}]_{0}^{0.75}

Simplify

= 2 [0.5 x^{2}]_{0}^{0.75}

Compute the boundaries:

0.28125

= 2 \cdot 0.28125

Simplify

= 0.5625

\frac{d}{d x} (A x^{- \frac{1}{2}})

x = y \frac{1}{3}, x = 0, y = 64

(y^{2} + y x) d x + x^{2} d y = 0

\frac{4 x ^{5}}{e ^{3 x}}

x \to 0 - lim (\frac{e ^{x}}{1 - e ^{x}})

What is the integral from 0 to 0.75 of 2x ?
The integral from 0 to 0.75 of 2x is 0.5625