What is laplacetransform e^{-3t}sin(t) ?

The answer to laplacetransform e^{-3t}sin(t) is 1/((s+3)^2+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform e^{-3t}sin(t)

laplace transform

e^{- 3 t} sin (t)

\frac{1}{( s + 3 ) ^{2} + 1}

Solution steps

L {e^{- 3 t} sin (t)}

Apply transform rule:

L {f (t)} = F (s)

then

L {e^{a t} f (t)} = F (s - a)

For

e^{- 3 t} sin (t) : f (t) = sin (t), a = - 3

= L {sin (t)} (s + 3)

L {sin (t)} : \frac{1}{s ^{2} + 1}

= \frac{1}{( s + 3 ) ^{2} + 1}

\frac{d y}{d x} = (\frac{- 2 y}{( x - 2 )})

x \to 0 + lim (- 1)

\int 6 (x + 2) d x

x \to 0 lim (\frac{x}{x ^{2}})

\int \frac{a x + b}{a ^{2} x ^{2} + b ^{2}} d x

What is laplacetransform e^{-3t}sin(t) ?
The answer to laplacetransform e^{-3t}sin(t) is 1/((s+3)^2+1)