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Popular >

y^'= 1/(2y)

Solution

y^{^{'}} = \frac{1}{2 y}

Solution

y = t + c_{1}, y = - t + c_{1}

Solution steps

y^{'} (t) = \frac{1}{2 y}

Solve separable ODE:

y = t + c_{1}, y = - t + c_{1}

y = t + c_{1}, y = - t + c_{1}

Popular Examples

integral of 1/((x+3)sqrt(x^2+6x+5))

\int \frac{1}{( x + 3 ) x ^{2} + 6 x + 5} d x

limit as x approaches 2 of (x-3)^2

x \to 2 lim ((x - 3)^{2})

integral of sec^5(x

\int sec^{5} (d) x d x

integral from 0 to 5 of 20e^{0.02x}

\int_{0}^{5} 20 e^{0.02 x} d x

derivative of f(x)=(x^3)/(12)+1/x derivative of

f (x) = \frac{x ^{3}}{12} + \frac{1}{x}

Frequently Asked Questions (FAQ)

What is the solution for y^'= 1/(2y) ?
The solution for y^'= 1/(2y) is y=sqrt(t+c_{1)},y=-sqrt(t+c_{1)}