What is the limit as x approaches 0-of 1-3/x+1/(x^2) ?

The limit as x approaches 0-of 1-3/x+1/(x^2) is infinity

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limit as x approaches 0-of 1-3/x+1/(x^2)

x \to 0 - lim (1 - \frac{3}{x} + \frac{1}{x ^{2}})

\infty

Solution steps

x \to 0 - lim (1 - \frac{3}{x} + \frac{1}{x ^{2}})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 - lim (1) - x \to 0 - lim (\frac{3}{x}) + x \to 0 - lim (\frac{1}{x ^{2}})

x \to 0 - lim (1) = 1

x \to 0 - lim (\frac{3}{x}) = - \infty

x \to 0 - lim (\frac{1}{x ^{2}}) = \infty

= 1 - (- \infty) + \infty

Apply Infinity Property:

c + \infty = \infty

= \infty

y = (1 + 4 x)^{\frac{3}{2}}

\int x sin (\frac{nπ x}{3}) d x

\frac{1}{s ^{2} ( s ^{2} + 1 ^{2} )}

\int x \cdot arctan (x) d x

x (1 - \frac{4}{x + 3})

What is the limit as x approaches 0-of 1-3/x+1/(x^2) ?
The limit as x approaches 0-of 1-3/x+1/(x^2) is infinity