What is the derivative of (4x/(e^x)) ?

The derivative of (4x/(e^x)) is (4(1-x))/(e^x)

What is the first derivative of (4x/(e^x)) ?

The first derivative of (4x/(e^x)) is (4(1-x))/(e^x)

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\frac{d}{d x} (\frac{4 x}{e ^{x}})

\frac{4 ( 1 - x )}{e ^{x}}

Solution steps

\frac{d}{d x} (\frac{4 x}{e ^{x}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{x}{e ^{x}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 4 \cdot \frac{\frac{d x}{d x} e ^{x} - \frac{d}{d x} ( e ^{x} ) x}{( e ^{x} ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x}) = e^{x}

= 4 \cdot \frac{1 \cdot e ^{x} - e ^{x} x}{( e ^{x} ) ^{2}}

Simplify

4 \cdot \frac{1 \cdot e ^{x} - e ^{x} x}{( e ^{x} ) ^{2}} : \frac{4 ( 1 - x )}{e ^{x}}

= \frac{4 ( 1 - x )}{e ^{x}}

x \to 0 lim (\frac{1 cos ( 3 x )}{x})

\frac{3 x}{2}

7 e^{2}

\frac{\partial}{\partial x} (y z^{2})

\int x^{2} - 9 x + 4 d x

What is the derivative of (4x/(e^x)) ?
The derivative of (4x/(e^x)) is (4(1-x))/(e^x)
What is the first derivative of (4x/(e^x)) ?
The first derivative of (4x/(e^x)) is (4(1-x))/(e^x)