What is the solution for (dy)/(dx)+y/x =4x^8y^2 ?

The solution for (dy)/(dx)+y/x =4x^8y^2 is y= 2/(x(-x^8+c_{1))}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)+y/x =4x^8y^2

\frac{d y}{d x} + \frac{y}{x} = 4 x^{8} y^{2}

y = \frac{2}{x ( - x ^{8} + c _{1} )}

Solution steps

\frac{d y}{d x} + \frac{y}{x} = 4 x^{8} y^{2}

Solve Bernoulli ODE:

y = \frac{2}{x ( - x ^{8} + c _{1} )}

y = \frac{2}{x ( - x ^{8} + c _{1} )}

\frac{\partial}{\partial x} (- x^{4})

x^{2} y^{^{''}} + 3 x y^{^{'}} + y = 0, y (1) = 3.6, y^{^{'}} (1) = 0.4

\int_{- 1}^{7} 3 x + 7 d x

\frac{\partial}{\partial x} ((x - 4) ln (x y))

\int - x cos (x) + x d x

What is the solution for (dy)/(dx)+y/x =4x^8y^2 ?
The solution for (dy)/(dx)+y/x =4x^8y^2 is y= 2/(x(-x^8+c_{1))}