What is the solution for ((3y^2-x^2)/(y^5))(dy)/(dx)+x/(2y^4)=0 ?

The solution for ((3y^2-x^2)/(y^5))(dy)/(dx)+x/(2y^4)=0 is

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((3y^2-x^2)/(y^5))(dy)/(dx)+x/(2y^4)=0

(\frac{3 y ^{2} - x ^{2}}{y ^{5}}) \frac{d y}{d x} + \frac{x}{2 y ^{4}} = 0

y = \frac{- 3 + 2 c _{1} x ^{2} + 9}{2 c _{1}}, y = - \frac{- 3 + 2 c _{1} x ^{2} + 9}{2 c _{1}}, y = - \frac{2 c _{1} x ^{2} + 9 + 3}{2 c _{1}}, y = - - \frac{2 c _{1} x ^{2} + 9 + 3}{2 c _{1}}

Solution steps

(\frac{3 y ^{2} - x ^{2}}{y ^{5}}) \frac{d y}{d x} + \frac{x}{2 y ^{4}} = 0

Solve exact ODE:

y = \frac{- 3 + 2 c _{1} x ^{2} + 9}{2 c _{1}}, y = - \frac{- 3 + 2 c _{1} x ^{2} + 9}{2 c _{1}}, y = - \frac{2 c _{1} x ^{2} + 9 + 3}{2 c _{1}}, y = - - \frac{2 c _{1} x ^{2} + 9 + 3}{2 c _{1}}

y = \frac{- 3 + 2 c _{1} x ^{2} + 9}{2 c _{1}}, y = - \frac{- 3 + 2 c _{1} x ^{2} + 9}{2 c _{1}}, y = - \frac{2 c _{1} x ^{2} + 9 + 3}{2 c _{1}}, y = - - \frac{2 c _{1} x ^{2} + 9 + 3}{2 c _{1}}

\frac{\partial}{\partial x} (x (x^{2} + 1))

\frac{3}{s - 5} - \frac{2}{s + 7}

\int b^{x} d x

\frac{d y}{d x} = \frac{( x ^{2} + 1 )}{e ^{y}}

\int (\frac{x ^{2}}{1 - x ^{2}}) d x

What is the solution for ((3y^2-x^2)/(y^5))(dy)/(dx)+x/(2y^4)=0 ?
The solution for ((3y^2-x^2)/(y^5))(dy)/(dx)+x/(2y^4)=0 is