What is the derivative of x^2+e^x ?

The derivative of x^2+e^x is 2x+e^x

What is the first derivative of x^2+e^x ?

The first derivative of x^2+e^x is 2x+e^x

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derivative of

x^{2} + e^{x}

2 x + e^{x}

Solution steps

\frac{d}{d x} (x^{2} + e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (e^{x})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (e^{x}) = e^{x}

= 2 x + e^{x}

\frac{d}{d x} ((x^{2} + x) (x^{2} - x))

\frac{d}{d x} (x - 9)

\frac{\partial}{\partial x} (\frac{x - y}{x + 2 y})

\frac{d}{d x} (\frac{sin ( \frac{1}{x} )}{x ^{2}})

x \to - \infty lim (9)

What is the derivative of x^2+e^x ?
The derivative of x^2+e^x is 2x+e^x
What is the first derivative of x^2+e^x ?
The first derivative of x^2+e^x is 2x+e^x