What is the integral of-(1400)/(x^2) ?

The integral of-(1400)/(x^2) is (1400)/x+C

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integral of-(1400)/(x^2)

\int - \frac{1400}{x ^{2}} d x

\frac{1400}{x} + C

Solution steps

\int - \frac{1400}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 1400 \cdot \int \frac{1}{x ^{2}} d x

Apply the Power Rule

: - \frac{1}{x}

= - 1400 (- \frac{1}{x})

Simplify

- 1400 (- \frac{1}{x}) : \frac{1400}{x}

= \frac{1400}{x}

Add a constant to the solution

= \frac{1400}{x} + C

x \to - 1 + lim (6 x^{2} + 11)

\int cos^{7} (\frac{1}{5} x) d x

\int t^{2} e^{- 10 t} d t

\frac{\partial}{\partial x} (- 6 x y sin (x y^{2}))

3 x, \frac{1}{x}, 8, 1

What is the integral of-(1400)/(x^2) ?
The integral of-(1400)/(x^2) is (1400)/x+C