What is implicit (dy)/(dx),8cos(6x)sin(4y)=3 ?

The answer to implicit (dy)/(dx),8cos(6x)sin(4y)=3 is (dy)/(dx)=(3sin(4y)sin(6x))/(2cos(4y)cos(6x))

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implicit (dy)/(dx),8cos(6x)sin(4y)=3

implicit derivative

\frac{d y}{d x}, 8 cos (6 x) sin (4 y) = 3

\frac{d y}{d x} = \frac{3 sin ( 4 y ) sin ( 6 x )}{2 cos ( 4 y ) cos ( 6 x )}

Solution steps

8 cos (6 x) sin (4 y) = 3

Treat

y

y (x)

Differentiate both sides:

8 (- 6 sin (4 y) sin (6 x) + 4 cos (4 y) cos (6 x) \frac{d y}{d x}) = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{3 sin ( 4 y ) sin ( 6 x )}{2 cos ( 4 y ) cos ( 6 x )}

\frac{d y}{d x} = \frac{3 sin ( 4 y ) sin ( 6 x )}{2 cos ( 4 y ) cos ( 6 x )}

\int \frac{25}{9} sin^{2} (x) d x

\int \frac{x ^{2} - 3 x + 7}{x ^{3} + x} d x

f (x) = - 12

\int x^{2} 9 + x^{3} d x

\int x (4 x^{2} + 5)^{7} d x

What is implicit (dy)/(dx),8cos(6x)sin(4y)=3 ?
The answer to implicit (dy)/(dx),8cos(6x)sin(4y)=3 is (dy)/(dx)=(3sin(4y)sin(6x))/(2cos(4y)cos(6x))