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Popular >

y^'=5(y-t^2)

Solution

y^{^{'}} = 5 (y - t^{2})

Solution

y = t^{2} + \frac{2 t}{5} + \frac{2}{25} + c_{1} e^{5 t}

Solution steps

y^{'} (t) = 5 (y - t^{2})

Solve linear ODE:

y = t^{2} + \frac{2 t}{5} + \frac{2}{25} + c_{1} e^{5 t}

y = t^{2} + \frac{2 t}{5} + \frac{2}{25} + c_{1} e^{5 t}

Popular Examples

x y^{^{'}} + 2 y + x = 1

derivative of x(x-9^2)

\frac{d}{d x} (x (x - 9)^{2})

(xdy)/(dx)=y+x^2sin(x)

\frac{x d y}{d x} = y + x^{2} sin (x)

integral of (1/3 x-9)^{2/3}

\int (\frac{1}{3} x - 9)^{\frac{2}{3}} d x

integral of-25sin(5x)

\int - 25 sin (5 x) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=5(y-t^2) ?
The solution for y^'=5(y-t^2) is y=t^2+(2t)/5+2/25+c_{1}e^{5t}