What is the integral of (x^2-5)^2 ?

The integral of (x^2-5)^2 is (x^5)/5-(10x^3)/3+25x+C

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integral of (x^2-5)^2

\int (x^{2} - 5)^{2} d x

\frac{x ^{5}}{5} - \frac{10 x ^{3}}{3} + 25 x + C

Solution steps

\int (x^{2} - 5)^{2} d x

Expand

(x^{2} - 5)^{2} : x^{4} - 10 x^{2} + 25

= \int x^{4} - 10 x^{2} + 25 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{4} d x - \int 10 x^{2} d x + \int 25 d x

\int x^{4} d x = \frac{x ^{5}}{5}

\int 10 x^{2} d x = \frac{10 x ^{3}}{3}

\int 25 d x = 25 x

= \frac{x ^{5}}{5} - \frac{10 x ^{3}}{3} + 25 x

Add a constant to the solution

= \frac{x ^{5}}{5} - \frac{10 x ^{3}}{3} + 25 x + C

\int \frac{x}{x} d x

y = 11 x^{- 2} + 7 x^{3} - 5 x

x \to 2 lim (4)

x \to - 6 + lim (tan (\frac{π x}{4}))

\int (3 x^{3} - 5 x^{2} + 3 x + 4) d x

What is the integral of (x^2-5)^2 ?
The integral of (x^2-5)^2 is (x^5)/5-(10x^3)/3+25x+C