What is the integral of 9/(sqrt(1-x^2)) ?

The integral of 9/(sqrt(1-x^2)) is 9arcsin(x)+C

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integral of 9/(sqrt(1-x^2))

\int \frac{9}{1 - x ^{2}} d x

9 arcsin (x) + C

Solution steps

\int \frac{9}{1 - x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int \frac{1}{1 - x ^{2}} d x

Use the common integral:

\int \frac{1}{1 - x ^{2}} d x = arcsin (x)

= 9 arcsin (x)

Add a constant to the solution

= 9 arcsin (x) + C

\frac{d}{d x} (ln (5 x - 4))

\int \frac{1}{x ^{2} - 6 x + 34} d x

y^{^{''}} + y = - sin (3 x)

\frac{d}{d x} (2 sin (π x))

\frac{d}{d x} (e^{\frac{4 x}{3}})

What is the integral of 9/(sqrt(1-x^2)) ?
The integral of 9/(sqrt(1-x^2)) is 9arcsin(x)+C