What is area y=2x^2,y=2x+6 ?

The answer to area y=2x^2,y=2x+6 is -(8sqrt(13))/3+7sqrt(13)

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area y=2x^2,y=2x+6

area

y = 2 x^{2}, y = 2 x + 6

- \frac{8 13}{3} + 713

Solution steps

Apply the area formula:

\int_{\frac{1 - 13}{2}}^{\frac{1 + 13}{2}} 2 x^{2} - (2 x + 6) d x

Solve

\int_{\frac{1 - 13}{2}}^{\frac{1 + 13}{2}} 2 x^{2} - (2 x + 6) d x : - \frac{8 13}{3} + 713

The area is:

= - \frac{8 13}{3} + 713

ln (x)

\frac{d}{d x} (\frac{e ^{x} - e ^{- x}}{5})

\frac{x d y}{d x} = y + x^{2} - y^{2}

\int_{- \frac{1}{4}}^{\frac{1}{4}} \frac{1}{1 - x ^{2}} d x

- 9 t^{2}

What is area y=2x^2,y=2x+6 ?
The answer to area y=2x^2,y=2x+6 is -(8sqrt(13))/3+7sqrt(13)