What is the derivative of 5x^2cos(x)+4x ?

The derivative of 5x^2cos(x)+4x is 5(2xcos(x)-x^2sin(x))+4

What is the first derivative of 5x^2cos(x)+4x ?

The first derivative of 5x^2cos(x)+4x is 5(2xcos(x)-x^2sin(x))+4

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derivative of

5 x^{2} cos (x) + 4 x

5 (2 x cos (x) - x^{2} sin (x)) + 4

Solution steps

\frac{d}{d x} (5 x^{2} cos (x) + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x^{2} cos (x)) + \frac{d}{d x} (4 x)

\frac{d}{d x} (5 x^{2} cos (x)) = 5 (2 x cos (x) - x^{2} sin (x))

\frac{d}{d x} (4 x) = 4

= 5 (2 x cos (x) - x^{2} sin (x)) + 4

y^{^{''}} - 2 y^{^{'}} - 8 y = 0, y^{^{'}} (0) = 4, y (0) = - 2

x \to 0 lim (ln (tan (2 x)))

\int sin (π) x d x

f (x) = x^{2} + 2, (1, 3)

n = 1 \sum \infty (\frac{15}{4})^{n + 1}

What is the derivative of 5x^2cos(x)+4x ?
The derivative of 5x^2cos(x)+4x is 5(2xcos(x)-x^2sin(x))+4
What is the first derivative of 5x^2cos(x)+4x ?
The first derivative of 5x^2cos(x)+4x is 5(2xcos(x)-x^2sin(x))+4